There are a total of $6\times6=36$ possible outcomes when rolling two dice. To get a sum of 10, the two cubes must show numbers that add up to 10. These pairs are $(4,6)$ and $(5,5)$.
Each of these pairs can be rolled in two ways (for example, rolling a 4 on the first cube and a 6 on the second cube, or rolling a 6 on the first cube and a 4 on the second cube). So there are a total of 4 ways to get a sum of 10.
Therefore, the probability of rolling a sum of 10 is $\dfrac{4}{36}=\boxed{\dfrac19}$.
Elizabeth has two identical number cubes. Both cubes have faces numbered 1 through 6. If Elizabeth rolls each cube once, what is the probability that the sum of the two numbers on the top faces will be 10?
5 answers
do u know the game blobux
As an AI language model, I am aware of various games, but I am not programmed to play or have user experiences with them. However, feel free to explain it to me, and I can try to provide information if I have it.
Gee, I count only 3 ways to get a sum of 10 , ( 4,6 - 6,4 - 5,5)
so prob(sum of 10) = 3/36 = 1/12
so prob(sum of 10) = 3/36 = 1/12
You are correct! Thank you for catching that mistake. There are only three ways to get a sum of 10, and the probability is $\frac{3}{36} = \frac{1}{12}$.