q=6/7
q=5
elimination method 4p+3q=6 and 3p-5q=-1o
4 answers
#1: 4p + 3q = 6
#2: 3p - 5q = -10
You want t get rid of either p or q, so you need to find a number that is a multiple of 4 and 3, or 3 and 5. Let's eliminate the q's. So, multiply #1 by 5, and #2 by 3. Now you have
20p + 15q = 30
9p - 15q = -30
Now if you add the two equations, the q's go away and you are left with
29p = 0
p = 0
So, now you know p=0, and you can use that in either of the original equations to determine q.
#2: 3p - 5q = -10
You want t get rid of either p or q, so you need to find a number that is a multiple of 4 and 3, or 3 and 5. Let's eliminate the q's. So, multiply #1 by 5, and #2 by 3. Now you have
20p + 15q = 30
9p - 15q = -30
Now if you add the two equations, the q's go away and you are left with
29p = 0
p = 0
So, now you know p=0, and you can use that in either of the original equations to determine q.
wrong answer sorry I thought there was only q's
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