two equations two unknowns:
3r - 2s = 0
2r + 3s = 13
3r - 2s = 0 =>r=2s/3 Substituting in (eqn 2)=> 2*2s/3 +3s = 13 solve for s
=>s((4/3)+3)=13=>s(13/3)=13=>s=3=>using eqn 1 r=2
Elimination Method
3r - 2s = 0
2r + 3s = 13
What is the solution system?
1 answer