t = (y-4)/2 from second equation
so
x = 4 [ (y-4)/2 ]^2
x = (y-4)^2
x = y^2 -8 y + 16
Eliminate the parameter t to find a Cartesian equation in the form x=f(y)
x(t)=4t^2
y(t)=4+2t
1 answer
x(t)=4t^2
y(t)=4+2t
1 answer