Eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve.

Question

x = secQ
Y = tanQ

Would I use cos^2Q + sin^2Q = 1?

Answer 1

x^2+y^2= 1/cos^2 + sin^2/cos^2
=x^2( 1+sin^2)=x^2(2-cos^2)=
= x^2 (2-1/x^2)= 2x^2-1
or
y^2-x^2=-1
x^2-y^2=1
check all that