eliminate parameters of x=1+cos t

Question

y=1-sin t

graph the parametric equations

Answer 1

x = 1 + cos t
y = 1 - sin t

cos t = (x-1)
sin t = (1-y)

cos^2 t = (x-1)^2
sin^2 t = (1-y)^2
----------------- add
1 = (x-1)^2 + (1-y)^2
your turn :)

Answer 2

why squared?

Answer 3

because I learned in a trig course the sin^2 x + cos^2 x = 1

Answer 4

what is the graph for this equation?

Answer 5

how to graph equation?

Answer 6

hey, just pick some points
note
x^2+y^2 = r^2 = circle

Answer 7

i didn't get a circle by using 0, pi/6, pi/4, pi/3, and pi/2?

Answer 8

how do you eliminate the parameters for x=1-t^2 and y=1+t?

Answer 9

t^2 = 1-x

t = y-1 so t^2 = y^2-2y+1
so
y^2-2y+1 = 1 - x

Answer 10

find directrix of 2/3=2 sin theta