Eli has 7 black pens and 5 blue pens in his desk drawer. He also has 3 yellow highlighters, 2 green highlighters, and 5 pink highlighters in his pencil case. If he chooses one pen and one highlighter without looking, what is the probability that he will get a black pen and he will not get a green highlighter?

Question

(1 point)
Responses

start fraction seven over fifteen end fraction
Image with alt text: start fraction seven over fifteen end fraction

Start Fraction 117 over 1,000 End Fraction
Image with alt text: Start Fraction 117 over 1,000 End Fraction

one-third
Image with alt text: one-third

start fraction 1 over 12 end fraction
Image with alt text: start fraction 1 over 12 end fraction
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Answer 1

Start Fraction 117 over 1,000 End Fraction

The probability of choosing a black pen is 7/15, and the probability of not choosing a green highlighter is 10/12 (since there are 2 green highlighters out of a total of 12 highlighters).

Therefore, the probability of both events happening is (7/15) x (10/12) = 117/1000.