In order to determine the mass of element B present when 48g of element A reacts, we need to first determine the number of moles of element A present.
Given that the molar mass of element A is 4g/mol, 48g of element A is equal to 48g / 4g/mol = 12 moles of element A.
From the balanced equation, it is seen that 3 moles of A₂ react with every 2 moles of B to produce 2 moles of A₃B. Therefore, the molar ratio of A to B is 3:2.
Since we have 12 moles of element A, we can calculate the moles of element B using the ratio:
12 moles A x (2 moles B / 3 moles A) = 8 moles B
Next, we can determine the mass of element B present:
8 moles B x 16g/mol = 128g
Therefore, when 48g of element A is present, there should be 128g of element B present. The correct answer is 128g.
Elements A and B react according to the following balanced equation. 3A2+2B → 2A3B The molar mass of element A is 4g/mol. The molar mass of element B is 16g/mol. When the initial mass of element A is 48g, which mass of element B should be present? (1 point) Responses 192g 192g 64g 64g 96g 96g 128g
1 answer
1 answer