Element x has the highest first electron affinity in its period, the ground state electron configuration of its common is: [Kr] 5s2 4d10 5p6
Element Y is the second largest element in its period; its valence electron are in orbital(s) that have n= 6.
What is the most stable compound formed when elements X and Y are combined:_________
How'd you figure this question out?
3 answers
Would you proof your post please. I think a word is missing "of its common .....is". I wonder if the missing word is ion. As posted element X makes no sense; in fact, [Kr]5s2 4d10 5p6 is Xe and that has the lowest electron affinity in its period. I've spent half an hour on this and realized something must be wrong with the post.
Yes it is "most common ion is: [Kr] 5s2 4d10 5p6".
I have also spent quite a long time trying to figure this question out.
The answer key said it's BaI2, which confused me more.
I have also spent quite a long time trying to figure this question out.
The answer key said it's BaI2, which confused me more.
I spent most of my time trying to figure out how all of that could be a compound of Xe until I realized it could NOT be and ion was the mission word/ I'm glad you confirmed that.
Do I assume you need an explanation of why it is BaI2?
The electron affinity increases from left to right in the table so you look at Kr, then you see that 4d10 5s2 5p6 adds to 18 so that element must be Xe. Since it's the ION, that makes the element {Kr] 4d10 5s2 5p5 and that is I and I has the highest electron affinity in that period. That's element X.
Y is the second largest element in the period with n = 6. Size decreases as you go from left to right in the periodic table (see link below) so Cs must the largest and that makes Ba the second largest. Y must be Ba. BaI2 follows from all of that.
http://crystalmaker.com/support/tutorials/crystalmaker/atomic-radii/index.html
Hope this helps.
Do I assume you need an explanation of why it is BaI2?
The electron affinity increases from left to right in the table so you look at Kr, then you see that 4d10 5s2 5p6 adds to 18 so that element must be Xe. Since it's the ION, that makes the element {Kr] 4d10 5s2 5p5 and that is I and I has the highest electron affinity in that period. That's element X.
Y is the second largest element in the period with n = 6. Size decreases as you go from left to right in the periodic table (see link below) so Cs must the largest and that makes Ba the second largest. Y must be Ba. BaI2 follows from all of that.
http://crystalmaker.com/support/tutorials/crystalmaker/atomic-radii/index.html
Hope this helps.
3 answers