E = 550 V/0.0125m = 44,000 V/m
The force on the particle is not needed to compute the field, but can be used to compute the charge on the oil (?) drop. Why do you call it an o drop?
Electric plates are 1.25cm apart, An o drop that weighs 1.1968x10^13 N is suspended between the plates when the potential differences across them is 550.0 volts.
What is the electric field intensity between the plates?
2 answers
Sorry , didn't realized I just put o.
It's really suppose to be oil.
But then how do I go about finding how many excess electrons are on the oil drop?
It's really suppose to be oil.
But then how do I go about finding how many excess electrons are on the oil drop?