To determine which ordered pair is part of the solution set for the equation \( y = 4x + 2 \), we need to substitute \( x \) from each ordered pair into the equation and see if we get the corresponding \( y \) value.
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For \( (3, 45) \): \[ y = 4(3) + 2 = 12 + 2 = 14 \quad \text{(Not a solution)} \]
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For \( (3, 14) \): \[ y = 4(3) + 2 = 12 + 2 = 14 \quad \text{(Is a solution)} \]
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For \( (3, 12) \): \[ y = 4(3) + 2 = 12 + 2 = 14 \quad \text{(Not a solution)} \]
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For \( (3, 7) \): \[ y = 4(3) + 2 = 12 + 2 = 14 \quad \text{(Not a solution)} \]
Therefore, the only ordered pair that is part of the solution set is \( (3, 14) \).