Let's analyze the numbers involved in the calculation. The expression is \(6 - \sqrt{6}\) and \(\frac{2}{3}\).
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Identifying the nature of the numbers:
- \(6\) is a rational number.
- \(\sqrt{6}\) is an irrational number.
- Therefore, \(6 - \sqrt{6}\) combines a rational number \(6\) with an irrational number \(\sqrt{6}\), resulting in an irrational number.
- \(\frac{2}{3}\) is a rational number.
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Now let's formally define the product:
- The product is \((6 - \sqrt{6}) \cdot \frac{2}{3}\).
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Rational and Irrational products:
- The product of a rational number and an irrational number is always irrational.
Given this analysis, here is the summary of the statements made:
- Elaina: Incorrect because she claims both numbers are irrational. Only \(6 - \sqrt{6}\) is irrational, while \(\frac{2}{3}\) is rational.
- Miguel: Incorrect because he claims both numbers are rational. One number is irrational.
- Swati: Correct because she states that the product of a rational number (\(\frac{2}{3}\)) and an irrational number (\(6 - \sqrt{6}\)) will indeed be irrational.
Thus, the correct answer is Swati.