Let \( S \) be the total savings that Edward has.
Edward spent \( \frac{2}{15}S \) on renovating his office and \( \frac{1}{3}S \) on buying a car. The problem states that he spent $39,000 more on the car than on the renovations, which we can express mathematically as:
\[ \frac{1}{3}S = \frac{2}{15}S + 39000 \]
To solve for \( S \), we first convert \( \frac{1}{3}S \) to a fraction with a denominator of 15:
\[ \frac{1}{3}S = \frac{5}{15}S \]
Now we can rewrite the equation:
\[ \frac{5}{15}S = \frac{2}{15}S + 39000 \]
Next, we subtract \( \frac{2}{15}S \) from both sides:
\[ \frac{5}{15}S - \frac{2}{15}S = 39000 \]
This simplifies to:
\[ \frac{3}{15}S = 39000 \]
Which further simplifies to:
\[ \frac{1}{5}S = 39000 \]
To find \( S \), we multiply both sides by 5:
\[ S = 39000 \times 5 = 195000 \]
Now, we have Edward's total savings:
\[ S = 195000 \]
Next, we will calculate how much he spent on the renovations and the car:
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Renovation: \[ \frac{2}{15}S = \frac{2}{15} \times 195000 = 2 \times 13000 = 26000 \]
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Car: \[ \frac{1}{3}S = \frac{1}{3} \times 195000 = 65000 \]
To confirm that he spent \( 39000 \) more on the car than on the renovation:
\[ 65000 - 26000 = 39000 \]
Now, we can find his remaining savings after these expenditures:
\[ \text{Remaining Savings} = S - \left( \text{Amount spent on renovations} + \text{Amount spent on car} \right) \] \[ = 195000 - (26000 + 65000) \] \[ = 195000 - 91000 = 104000 \]
Thus, Edward has \(\boxed{104000}\) left in savings.