Edgar and his cousin are driving bumper cars at an amusement park. When his cousin gets stuck in a corner, Edgar drives his car into his cousin’s car. The combined mass of Edgar and his bumper car is 268 kilograms. Edgar is traveling at 2.2 meters per second. How much kinetic energy does Edgar have when he hits his cousin’s car?

Question

KE=12mv2

(1 point)
Responses

2,594.24 J
2,594.24 J

1,297.12 J
1,297.12 J

294.8 J
294.8 J

648.56 J

Answer 1

To calculate the kinetic energy (KE) of Edgar when he hits his cousin's car, we can use the formula:

\[ KE = \frac{1}{2} mv^2 \]

where:

• \( m \) is the mass (in kilograms),
• \( v \) is the velocity (in meters per second).

Given:

• \( m = 268 \) kg (the mass of Edgar and his bumper car),
• \( v = 2.2 \) m/s.

Now, substituting the values into the formula:

\[ KE = \frac{1}{2} \times 268 , \text{kg} \times (2.2 , \text{m/s})^2 \]

Calculating \( (2.2 , \text{m/s})^2 \):

\[ (2.2)^2 = 4.84 \]

Now, substituting this back into the kinetic energy formula:

\[ KE = \frac{1}{2} \times 268 \times 4.84 \]

Calculating \( \frac{1}{2} \times 268 = 134 \):

\[ KE = 134 \times 4.84 \]

Now, multiplying:

\[ KE = 646.56 , \text{J} \]

So, the answer rounded to two decimal places is \( 648.56 , \text{J} \).

The correct response is:

648.56 J