Eddie and his sister walked from home to school. His sister started walking at 8:00am at an average speed of 50 m/min. Eddie started walking at 8:05 at a speed of 60 m/min. Eddie caught up with his sister at mid-point between the school and his home. Find the distance between Eddie's home and the school.

Question

Please help, thank you so much

Answer 1

Let the distance between home and school be 2x
So they met after x metres.

Sister went for t minutes at 50 m/min , so x = 50t
Eddie went for (t-5) minutes at 60 m/min so x = 60(t-5)
but those are equal, so
60(t-5) = 50t
60t - 300 = 50t
t = 30

then x = 50(30) m = 1500 m
and the school is 3000 m or 3 km from home

Answer 2

Got it. Thanks