Ed is planning to put up a rectangular garden with a fixed area of 120m^2. If the dimension of the garden have to be whole numbers,determine the dimension that will require the least amount of fencing materials to enclose the garden.

Answer 1

What measurements would make this closest to a square?

Answer 2

10 and 12?
I need algebraic solution for this hehe I don't know how

Answer 3

x y = 120
120 = 12*10
11 * 11 would not quite work, close though :)
would you use 6*20 ????

Answer 4

@damon, do youu know algebraic process of it?

Answer 5

Length = X meters
Width = x-1 meters

x * (x-1) = 120.
x^2 - x = 120,
x^2 - x - 120 = 0,
Use Quad. Formula.
X = (-B +- sqrt(B^2-4AC))/2A. m.
X = (1 +- sqrt(1 + 480))/2 = 11.5 and -10.5.
X = 12 m. = Length.
L * W = 120,
12 * W = 120,
W = 10 m.