To find the weight of the original sample, we need to multiply the weight of each batch by the number of batches.
Weight of each batch: 3.9 x 10^-53.9 x 10^-5 grams.
(Note: Since the powers are the same, we can add them)
Weight of each batch = 3.9 x 10^(-53.9 - 5) grams
Weight of each batch = 3.9 x 10^-58.9 grams
Now, multiply the weight of each batch by the number of batches:
Weight of original sample = 3.9 x 10^-58.9 grams/batch x 88 batches
Weight of original sample = 3.9 x 10^(-58.9 + log10(88)) grams
Weight of original sample = 3.9 x 10^(-58.9 + 1.9459) grams
Weight of original sample = 3.9 x 10^(-56.9541) grams
Therefore, the original sample weighed 3.9 x 10^(-56.9541) grams.
Easton broke a cell sample into 88 batches, each weighing 3, point, 9, times, 10, to the power minus 53.9×10
−5
grams. How much did the original sample weigh? Use scientific notation to express your answer.
1 answer