Earl N. Meyer found that it took 26.54 mL of a 0.0100 M KOH solution to reach the equivalence point for the titration of 25.00 mL of HCL. What is the molarity of the HCL?

Answer 1

mLNaOH x M NaOH = mLHCl x M HCl
Solve for the one unknown.

Answer 2

Where do I get the variable from? Where does NaOH come from?

Answer 3

First off, I wrote NaOH instead of KOH.
mL KOH = 26.54
M KOH = 0.0100
mL HCl = 25.00
M HCl = ??

Answer 4

0.01062M