Each time the same letter appears it represents the same digit.Different letters represent different digits.C+C=D;D+E=17;A+2C=D;2B+C=8.Find the sum A+B+C+D+E

Answer 1

we have 2C=D, so
A+D=D
A=0

D+E=17
4B+D=16

17-E=4B

so, we have
(E,B)=(1,4)
(E,B)=(5,3)
(E,B)=(9,2)

that leaves us
(A,B,C,D,E) = (0,4,0,0,1) nope
(A,B,C,D,E) = (0,3,2,4,5) nope
(A,B,C,D,E) = (0,2,4,8,9) ok
so, A+B+C+D+E=23