each tablespoon of the liquid contains 95mg of aluminum hydroxide and 412mg of magnesium carbonate.how many moles of hydronium ion can be neutralized by one tablespoon of it?al(oh)3 =78g/mol
;mgCo3 =84.3 g/mol
2 answers
why it is nesessary to cool down the sample before titration in antacid anlaysis ?
If you take many more chemistry courses you will NOT be able to get away with using lower case for formulas. mgCo3 actually means milligrams carbon + o3 means nothing.
To solve the problem, first write the equations and balance them.
Al(OH)3 + 3H^+ ==> Al^+3 + 3H2O
Mg(OH)2 + 2H^+ ==> Mg^+2 + 2H2O
moles Al(OH)3 in 95 mg = grams/molar mass.
moles Mg(OH)2 in 412 mg = grams/molar mass.
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles H^+.
Do the same for Mg(OH)2.
Then add moles H^+ from the Al compound to moles H^+ from the Mg compound to arrive at the total moles H^+ neutralized by a table spoon of the stuff.
To solve the problem, first write the equations and balance them.
Al(OH)3 + 3H^+ ==> Al^+3 + 3H2O
Mg(OH)2 + 2H^+ ==> Mg^+2 + 2H2O
moles Al(OH)3 in 95 mg = grams/molar mass.
moles Mg(OH)2 in 412 mg = grams/molar mass.
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles H^+.
Do the same for Mg(OH)2.
Then add moles H^+ from the Al compound to moles H^+ from the Mg compound to arrive at the total moles H^+ neutralized by a table spoon of the stuff.
1 answer