To solve the questions, let's break them down step by step.
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Find the best approximation of the number of bytes required for a page of a document: \[8113 \text{ B} = 8.113 \cdot 10^3 \text{ B}\] When rounding to 1 significant figure, we can approximate this as: \[8 \cdot 10^3 \text{ B}\] Therefore, the correct choice is: Choice B: \[8 \cdot 10^{3} \text{ B}\]
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Find the best approximation of the number of bytes that Rhonda's USB drive can hold: \[8{,}000{,}000{,}000 \text{ B} = 8 \cdot 10^9 \text{ B}\] So, the correct choice is: Choice B: \[8 \cdot 10^{9} \text{ B}\]
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Calculate approximately how many pages Rhonda's USB drive can hold: Given that each page requires \(8113 \text{ B}\): \[ \text{Number of pages} = \frac{8{,}000{,}000{,}000 \text{ B}}{8113 \text{ B}} \] Calculating this gives: \[ \text{Number of pages} \approx \frac{8{,}000{,}000{,}000}{8{,}113} \approx 985{,}000 \text{ pages} \] This can be approximated to \(1 \cdot 10^6\) pages.
Therefore, the correct choice is: Choice A: \[1 \cdot 10^6\] pages.
In summary, the answers are:
- B: \[8 \cdot 10^{3} \text{ B}\]
- B: \[8 \cdot 10^{9} \text{ B}\]
- A: \[1 \cdot 10^6\] pages