the 1st list has 46 words crossed out ... 100 - 54
the 2nd list has 25 words crossed out ... 100 - 75
the 3rd list has 20 words crossed out ... 100 - 80
the sum of the 2nd and 3rd lists is 45 ... 25 + 20
this is NOT enough to cancel the 46 words in the 1st list
not possible
Each of three players has written a list of 100 words. The lists are compared and all the words that appear in at least two lists are crossed out. Is it possible that 54 words remain in the first list, 75 in the second and 80 in the third?
1 answer