Each of the two congruent sides of an isosceles triangle are 10 centimeters more than 1/2 the length of the base. If the perimeter of the triangle is to be at most 100 centimeters, what is the maximum length of the base?

Answer 1

2 [ (b/2)+10 ] + b </= 100

b + 20 + b </= 100

2 b </= 80

b </= 40

so 40 cm