no idea what the regions are. But if f(x) = F'(x), then the areas are
x^3+2x+F(x)[2,4]
= (64+8+F(4))-(8+4+F(2))
Presumably you have some way of finding F(x)
Each of the regions A, B, and C bounded by f(x) and the x-axis has area 5. Find the value of
∫2 [f(x)+3x^2+2]dx.
−4
I know to solve I can find the antiderivative of the equation but im not sure how to do this because of the f(x) in the parentheses.
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