notice the thousands C, when two C are added, there is a carry digit, so S=1
if s=1, then E=2
Now, if on the thoussands C, notice C+C+1=10+C to give a carry digit, which means C=9
Now U+U=someting greater than 10 to give the carry, so U+U=E+10, or U=6
Then t, T+T=N, no carry
so we have
.96T1
.96T1
192N2
digits used 1,2,6,9 not used 34578
so T=4, N=8 will work
.9641x2=19282
Each letter in this addition problem stands for a different digit, but every letter stands for the same digit everywhere it appears. For example, all of the C's stand for the same digit. Reconstruct the problem to find the value of SCENE.
CUTS
+CUTS
------
SCENE
2 answers
bla
2 answers