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Each figure is a parallelogram. Use the properties of parallelograms to find the value of x Finish the equation: 3x−5 Solve the...Asked by kino
Each figure is a parallelogram. Use the properties of parallelograms to find the value of x
Finish the equation: 6x+14
Solve the equation and state the value of x.
x=
Finish the equation: 6x+14
Solve the equation and state the value of x.
x=
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Answered by
GPT-4o mini
To solve for \( x \) using the properties of parallelograms, we first note that opposite angles and sides of a parallelogram are equal.
Assuming that you are referring to opposite angles or sides that are represented in an equation (though it appears you may need to provide the complete equation), I will give you an example.
Let's say you are comparing two opposite angles in a parallelogram, represented by the equation:
\[
6x + 14 = 180
\]
1. **Set the equation**: \( 6x + 14 = 180 \)
2. **Isolate the term with \( x \)**:
- Subtract 14 from both sides:
\[
6x = 180 - 14
\]
\[
6x = 166
\]
3. **Solve for \( x \)**:
- Divide both sides by 6:
\[
x = \frac{166}{6}
\]
\[
x = 27.67 \text{ (to 2 decimal places)}
\]
### Final Result
- If the equation you are working with is \( 6x + 14 = 180 \), then:
\[
x \approx 27.67
\]
If this wasn't the case and you meant something different, please provide additional context or the complete equation.
Assuming that you are referring to opposite angles or sides that are represented in an equation (though it appears you may need to provide the complete equation), I will give you an example.
Let's say you are comparing two opposite angles in a parallelogram, represented by the equation:
\[
6x + 14 = 180
\]
1. **Set the equation**: \( 6x + 14 = 180 \)
2. **Isolate the term with \( x \)**:
- Subtract 14 from both sides:
\[
6x = 180 - 14
\]
\[
6x = 166
\]
3. **Solve for \( x \)**:
- Divide both sides by 6:
\[
x = \frac{166}{6}
\]
\[
x = 27.67 \text{ (to 2 decimal places)}
\]
### Final Result
- If the equation you are working with is \( 6x + 14 = 180 \), then:
\[
x \approx 27.67
\]
If this wasn't the case and you meant something different, please provide additional context or the complete equation.
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