One leg, half the base, and the altitude form a right triangle. The angle opposite the altitude is 42 degrees. Draw a figure and see.
leg length = (L/2)/cos 42 = 9.82 foot (round to 9.8)
altitude = (L/2) tan 42 = 6.57 foot
(round to 6.6)
Each base angle of an isosceles triangle measures 42°. The base is 14.6 feet long.
A) Find the length of a leg of the triangle. Round to the nearest tenth of a foot.
B) Find the altitude of the triangle. Round to the nearest tenth of a foot.
1 answer
1 answer