(e^x + e^-x)/2=1
2 answers
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let e^x = y
y + 1/y = 2
y^2 - 2y + 1 = 0
(y-1)^2 = 0
y = 1
so e^x = 1 ----> x = 0
y + 1/y = 2
y^2 - 2y + 1 = 0
(y-1)^2 = 0
y = 1
so e^x = 1 ----> x = 0