Your notation is incorrect.
"2ln" doesn't mean anything
By definition, ln(e^k) = k
so, let's start over:
e^(x-2) = 12^(2x+3)
take ln of both sides:
x-2 = (2x+3) ln 12
x - 2 = 2ln12 x + 3ln12
x(1 - 2ln12) = 2 + 3ln12
x = (2 + 3ln12)/(1 - 2ln12)
e^(x-2)-12^(2x+3)=0
Class is a college level math prep.
Sorry for previous post being incomplete.
I'm thinking:
ln^(x-2)=ln12^(2x+3)
(x-2)ln=(2x+3)ln12
xln-2ln=2xln(12)+3ln(12)
xln-2xln(12)= 2ln+3ln(12)
and not sure
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