e varies inversely (y-2).if e =12 when y=4,find e when y=6 and y when e=0.5..

Answer 1

The given statement "e varies inversely with (y-2)" can be written as:

e = k/(y-2)

where k is the constant of variation.

To find the value of k, we can use the given information that e = 12 when y = 4. Substituting these values into the equation, we get:

12 = k/(4-2)
12 = k/2
24 = k

So the constant of variation, k, is 24.

Now we can use this value of k to find e when y = 6. Substituting these values into the equation, we get:

e = 24/(6-2)
e = 24/4
e = 6

Therefore, when y = 6, e = 6.

To find y when e = 0.5, we can rearrange the equation:

e = 24/(y-2)

0.5 = 24/(y-2)

Cross multiplying, we get:

0.5(y-2) = 24

0.5y - 1 = 24

0.5y = 25

y = 50

Therefore, when e = 0.5, y = 50.