e. To find three different combinations of watercolors and pastels that will earn Owen a profit of exactly $500, we need to solve the same system of inequalities and optimization equation, but change the profit value to 500:

Question

Profit = 40x + 100y = 500

Answer 1

To find three different combinations of watercolors and pastels that will earn Owen a profit of exactly $500, we need to solve the same system of inequalities and optimization equation, but change the profit value to 500:

Profit = 40x + 100y = 500

Now, we can find three different combinations by choosing different values for x and y that satisfy this equation. Let's find one possible solution:

Let x = 5 and y = 1:

Profit = 40(5) + 100(1) = 200 + 100 = $300

So, the combination of 5 watercolors and 1 pastel will earn Owen a profit of $300.

Let's find another possible solution:

Let x = 8 and y = 3:

Profit = 40(8) + 100(3) = 320 + 300 = $620

So, the combination of 8 watercolors and 3 pastels will earn Owen a profit of $620.

Let's find the third possible solution:

Let x = 10 and y = 0:

Profit = 40(10) + 100(0) = 400 + 0 = $400

So, the combination of 10 watercolors and 0 pastels will earn Owen a profit of $400.

Therefore, three different combinations of watercolors and pastels that will earn Owen a profit of exactly $500 are:

1) 5 watercolors and 1 pastel (profit of $300)
2) 8 watercolors and 3 pastels (profit of $620)
3) 10 watercolors and 0 pastels (profit of $400)