Dylan and Isaac are working together on solving math problems. For every one problem that Dylan completes, Isaac completes four. If the number of problems solved by Isaac is twenty-six more than two times the number of problems solved by Dylan, how many problems has Isaac solved?

Answer 1

Let's say Dylan solved x problems.
If Isaac solved four problems for every one solved by Dylan, then the number of problems Isaac solved is 4x.
According to the problem, 4x = 2x + 26.
Subtracting 2x from both sides gives 2x = 26.
Dividing both sides by 2 gives x = 13.
Therefore, Dylan solved 13 problems, and Isaac solved 4 * 13 = 52 problems.