dy/dt = 10−0.2y
5 dy/dt = 50-y
dy/(50-y) = .2 dt
-ln(50-y) = .2t+c
y = ce^-.2t + 50
y(0) = 10, so
10 = c+50
c = -40
y = 50 - 40e^-.2t
dydt=10−0.2y, y(0)=10.
a. Solve this differential equation,
I tried solving it and I keep on getting 10. I dont know how to approach this question
2 answers
Do I plug in 0 for t?