dy\dx=x+1\square rod of x
where y=5
x= 4
from chapter 5 (integration)
2 answers
This question makes no sense to me.
Perhaps you want to know y(x), knowing the derivative
dy/dx = x + (1/sqrt x)
However, I am not sure from the way you typed it whether you mean this instead:
dy/dx = (x+1)/sqrt x
In either case, integrate to get y(x) with an unknown constant term.
Use the fact that y = 5 when x = 4 to get the constant.
In the first case, the integral is
y = x^2/2 -(1/2)*x^-3/2 + C
dy/dx = x + (1/sqrt x)
However, I am not sure from the way you typed it whether you mean this instead:
dy/dx = (x+1)/sqrt x
In either case, integrate to get y(x) with an unknown constant term.
Use the fact that y = 5 when x = 4 to get the constant.
In the first case, the integral is
y = x^2/2 -(1/2)*x^-3/2 + C
0 answers