the initial vertical velocity is __ (2650 m/s) * cos(41.9º)
the time of flight is the initial vertical velocity divided by the gravitational acceleration __ 2 * [(2650 m/s) * sin(41.9º)] / (9.8 m/s^2)
the horizontal velocity is __ (2.65 km/s) * cos(41.9º)
the range is the horizontal velocity multiplied by the flight time
During World War I, the Germans had a gun
called Big Bertha that was used to shell Paris.
The shell had an initial speed of 2.65 km/s at
an initial inclination of 41.9◦ to the horizontal.
The acceleration of gravity is 9.8 m/s
2
.
How far away did the shell hit?
Answer in units of km
1 answer
1 answer