During the second stage of a rocket launch the rockets upward velocity increases from 980 m/s to 9000 m/s with an average acceleration of 33 m/s*.

How long did the acceleration last??

3 answers

Use
v(t) = v(0) + ā t

Where
v(0)=980[m/s]
v(t)=9000[m/s]
ā=33[m/s²]

So:
9000 = 980 + 33 t

Solve for t
I'm stuck on this same question. What I can't figure out is how to solve for t?
.
a=33m/s*2 Vf=9000m/s Vi=980m/s ^T=?

^T=Vf-Vi/a

^T=9000m/s-980m/s/33m/s*2 = 8020m/s/33m/s*2

^T=243seounds.= 243/60seounds=4minutes.

The acceleration lasted for 4minutes.