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During the Olympic ice competition, Boris (m = 75 kg) glides at 1.8 m/s to a stationary Juliette (52 kg) and hangs on. How far...Asked by grey
During the Olympic ice competition, Boris (m = 75 kg) glides at 1.8 m/s to a stationary Juliette (52 kg) and hangs on. How far will the pair slide after the collision if the coefficient of kinetic friction between the ice and their skates is .042?
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Answered by
Damon
get V from momentum
(75 + 52) V = 75 (1.8)
calculate V
calculate (1/2) m V^2
friction force = .042 * m * g
friction force * distance = (1/2) m V^2
or actually m cancels
.042 g d = .5 V^2
(75 + 52) V = 75 (1.8)
calculate V
calculate (1/2) m V^2
friction force = .042 * m * g
friction force * distance = (1/2) m V^2
or actually m cancels
.042 g d = .5 V^2
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