During the Olympic ice competition, Boris (m = 75 kg) glides at 1.8 m/s to a stationary Juliette (52 kg) and hangs on. How far will the pair slide after the collision if the coefficient of kinetic friction between the ice and their skates is .042?

Answer 1

get V from momentum

(75 + 52) V = 75 (1.8)

calculate V

calculate (1/2) m V^2

friction force = .042 * m * g

friction force * distance = (1/2) m V^2
or actually m cancels
.042 g d = .5 V^2