During takeoff, an airplane, climbs with a speed of 180 m/s at an angle of 34º above the horizontal. The sun is shining directly overhead. How fast is the shadow of the plane moving along the ground? (That is, what is the magnitude of the horizontal component of the plane's velocity?)
3 answers
Xo = 180*cos34 = 149.2 m/s.
12342
Xo = 180*cos34 = 149.2 m/s
1 answer