To determine which equation is balanced, we need to ensure that the number of atoms of each element on the reactant side equals the number on the product side for each option.
Let's break down each option:
A. H2O + CO2 → C6H12O6 + O2
- Left: 2 H, 1 O (from H2O), 1 C, 2 O (from CO2) → Total: 2 H, 1 C, 3 O
- Right: 6 C, 12 H, 6 O (from C6H12O6), 2 O (from O2) → Total: 6 C, 12 H, 8 O
- Not balanced.
B. 12H2O + 3CO2 → C6H12O6 + O2
- Left: 24 H (from 12H2O), 12 O (from 12H2O), 3 C (from 3CO2), 6 O (from 3CO2) → Total: 24 H, 3 C, 18 O
- Right: 6 C, 12 H, 6 O (from C6H12O6), 2 O (from O2) → Total: 6 C, 12 H, 8 O
- Not balanced.
C. 10H2O + 5CO2 → C6H12O6 + 15O2
- Left: 20 H (from 10H2O), 10 O (from 10H2O), 5 C (from 5CO2), 10 O (from 5CO2) → Total: 20 H, 5 C, 20 O
- Right: 6 C, 12 H, 6 O (from C6H12O6), 30 O (from 15O2) → Total: 6 C, 12 H, 36 O
- Not balanced.
D. 6H2O + 6CO2 → C6H12O6 + 6O2
- Left: 12 H (from 6H2O), 6 O (from 6H2O), 6 C (from 6CO2), 12 O (from 6CO2) → Total: 12 H, 6 C, 18 O
- Right: 6 C, 12 H, 6 O (from C6H12O6), 12 O (from 6O2) → Total: 6 C, 12 H, 18 O
- Balanced.
Therefore, the balanced equation is D: 6H2O + 6CO2 → C6H12O6 + 6O2.
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