During one year in a school 5/8 of the students had measels 1/2 had chicken pox, and 1/8 had neither. What fraction of the school had both measels and chicken pox

Answer 1

Let's assume that there are a total of 8 students in the school. Out of these 8 students, 5/8 had measles. Therefore, 5/8 * 8 = 5 students had measles.

Out of these 8 students, 1/2 had chicken pox. Therefore, 1/2 * 8 = 4 students had chicken pox.

However, we know that 1/8 had neither measles nor chicken pox. Therefore, 1/8 * 8 = 1 student had neither measles nor chicken pox.

Now, let's calculate the number of students who had both measles and chicken pox by subtracting the number of students who had either measles or chicken pox from the total number of students.

Total number of students = 8
Number of students who had measles = 5
Number of students who had chicken pox = 4
Number of students who had neither measles nor chicken pox = 1

Number of students who had both measles and chicken pox = Total number of students - (Number of students who had measles + Number of students who had chicken pox + Number of students who had neither measles nor chicken pox)
= 8 - (5 + 4 + 1)
= 8 - 10
= -2

Since the result is negative, it means that there was an error in the information provided or the calculations made. Please double-check the given data.