IT has an initial velocity, and height.
so find the initial velocity...
vf^2=2ad
Vf= sqrt(2*.350*255)
so how much higher does it go?
1/2 m v^2=mgh
solve for h additional, and then it falls h + 255m to the ground.
d=2*habove+255
During launches, rockets often discard unneeded parts. A certain rocket starts from rest on the launch pad and accelerates upward at a steady 3.50 m/s^2. When it is 255 m above the launch pad, it discards a used fuel canister by simply disconnecting it. Once it is disconnected, the only force acting on the canister is gravity (air resistance can be ignored).
What total distance did the canister travel between its release and its crash onto the launch pad?
1 answer