During intermission, at a hockey game, small foam hockey pucks are launched from a height. How long is a puck in the air if a student in the stands catches it on its way down 12m above ice lvl? The model for the vertical motion of the puck can be approximated by the relation h=-5t^2+15t+2, where t is the time in seconds and h is the height in metres.

1 answer

well, just solve for t when

-5t^2 + 12t + 2 = 12

But I suspect a typo, since the maximum height reached is 9.2m

??