Question

During baseball practice, you go up into the bleachers to retrieve a ball. You throw the ball back into the playing field at an angle of 42deg above the horizontal, giving it an initial velocity of 15m/s. If the ball is 5.3m above the level of the playing field when you throw it, what will be the velocity of the ball when it hits the ground of the playing field?

Answer 1

Use energy:

Initial KE+initialPE=finalKE
1/2 m 15^2 + m*g*5.3= 1/2 m vf^2