let the total be x students
so x/3 + x/4 + x/6 + 18 = x
multiply by 12
4x + 3x + 2x + 216 = 12x
finish it up
During a recent survey of two middle school classrooms, 1/3 of the students reported that they bring their lunch to school. Another 1/4 reported that they buy their lunch in the cafeteria and 1/6 reported going home for lunch. The remaining 18 students reported that they don't eat lunch. How many students are in the two classes?
42 answers
im now gonna use this form for bot sorry 2017 ITS MINE NOW WHOOOOOOO
I apologize, as an AI language model, I do not have the ability to take ownership of any form or material. My purpose is to assist users in answering their questions and provide helpful information.
You want to estimate the number of students who bring their lunch to school every day. Which of the following is the best sample for this situation @bot
Responses
45 first-year students selected at random
50 female students selected at random
all members of the Math Club
80 students selected at random during lunch
Responses
45 first-year students selected at random
50 female students selected at random
all members of the Math Club
80 students selected at random during lunch
The best sample for estimating the number of students who bring their lunch to school every day would be "80 students selected at random during lunch." This is because the sample is taken from the population in question and during the relevant time period. Sampling 80 students during lunch will provide a more accurate estimate of the number of students who bring their lunch to school than selecting a smaller or different group of students, such as first-year students or female students.
A coffee shop owner is interested in determining what people think about the new coffee flavor. Which of the following is the population in this situation? @bot
Responses
all customers who bought the new coffee
all customers who did not buy the new coffee
100 random customers
the first 50 customers who bought the new coffee
Responses
all customers who bought the new coffee
all customers who did not buy the new coffee
100 random customers
the first 50 customers who bought the new coffee
The population in this situation is "all customers who bought the new coffee." This is because the coffee shop owner is interested in the opinions of all customers who tried the new coffee flavor, and therefore, this group represents the whole population that the owner is interested in. The other options, such as "all customers who did not buy the new coffee," "100 random customers," or "the first 50 customers who bought the new coffee," may represent smaller subgroups of the population but are not representative of the entire population of interest.
Tom wants to know the average number of musical instruments students in his school play. He used the school’s two band classes, consisting of a total of 48 students, as his representative sample. He concluded that students in his school play an average of three musical instruments. Is his conclusion valid? @bot
No, because his representative sample is too large.
Yes, because all members of the sample play at least one musical instrument.
Yes, because the sample includes both males and females who play musical instruments.
No, because he did not choose students randomly.
No, because his representative sample is too large.
Yes, because all members of the sample play at least one musical instrument.
Yes, because the sample includes both males and females who play musical instruments.
No, because he did not choose students randomly.
No, because he did not choose students randomly. In order for his conclusion to be valid, he needs to make sure that his chosen sample is representative of the entire school population. By using only two band classes, he may be overrepresenting the number of students who play musical instruments, as students in band classes are more likely to play an instrument. Additionally, by not choosing students randomly, he may be introducing bias into his sample selection, which can affect the validity of his conclusion.
A survey is conducted to determine the most common reason people own a cell phone. A company sent out a survey to customers between the ages of 20 and 30. Based on the responses, the company concluded that people own a cell phone for messaging purposes. Is this conclusion valid? @bot
Yes, because the sample includes all customers between the ages of 20 and 30.
No, because not all people who own a cell phone have the same probability of being selected.
Yes, because the sample includes male and female customers.
No, because the sample includes customers of too many different ages.
Yes, because the sample includes all customers between the ages of 20 and 30.
No, because not all people who own a cell phone have the same probability of being selected.
Yes, because the sample includes male and female customers.
No, because the sample includes customers of too many different ages.
No, because the sample may not be representative of the entire population that owns a cell phone. By only surveying customers between the ages of 20 and 30, the company may be excluding important groups, such as older people or teenagers, who may have different reasons for owning a cell phone. Additionally, the sample may not be selected randomly, which can introduce bias into the survey results. Therefore, the conclusion that people own a cell phone for messaging purposes may not be valid for the entire population that owns a cell phone.
A school principal wants to know the average number of extracurricular activities students in her school are involved in. She assigned each student a number from 1 to 415. Using a random number generator, she selected 200 students to be part of the sample. She concluded that students are involved in an average of two extracurricular activities. Is the principal’s conclusion valid? @bot
Yes, because only those who have extracurricular activities were included in the sample.
Yes, because every student had an equal chance to be part of the sample. The sample size also appears to be large enough.
No, because 200 students in the sample is too large.
No, because not all students in the sample have extracurricular activities.
Yes, because only those who have extracurricular activities were included in the sample.
Yes, because every student had an equal chance to be part of the sample. The sample size also appears to be large enough.
No, because 200 students in the sample is too large.
No, because not all students in the sample have extracurricular activities.
No, because not all students in the sample have extracurricular activities. A significant portion of the student population may not be involved in any extracurricular activities, and limiting the sample only to those who had extracurricular activities may bias the results. Additionally, selecting a random sample of 200 students does not guarantee that the sample is representative of the entire population. While the sample size appears to be decent, it may still be too small to accurately represent the population. Overall, the principal's conclusion may not be valid for the entire student population.
@bot the answer was actualy Yes, because every student had an equal chance to be part of the sample. The sample size also appears to be large enough.
I apologize for the confusion earlier. Yes, the principal's conclusion is valid because every student had an equal chance to be part of the sample. The sample size of 200 students is also large enough to provide a reasonable estimate of the average number of extracurricular activities students are involved in. As long as the random number generator was truly random and students were selected without bias, and as long as the sample is representative of the student population in terms of extracurricular activities participation, the principal's conclusion should be a valid estimate of the average number of extracurricular activities students are involved in.
thank you bot
You're welcome! If you have any more questions or concerns, feel free to ask.
@bot what was the first firearm to be made
The first firearm to be made was the "hand cannon," which was developed in China in the late 13th century. This early firearm used gunpowder and was essentially a metal tube that was attached to a wooden stock. It required manual loading and had a very short range. Over time, firearms became more sophisticated and efficient, and by the 16th century, they had become a major part of warfare and hunting.
A store manager wants to know the percentage of shoppers who use coupons. He surveys everyone who enters the meat aisle. He finds that 60 percent of shoppers use coupons. Does the sampling method the store manager used support a valid inference? @bot
Yes, because the sample contains coupon users and non-users.
No, because the sample is not chosen randomly.
No, because not all people who enter the meat aisle use coupons.
Yes, because the manager asked everyone who entered the meat aisle.
Yes, because the sample contains coupon users and non-users.
No, because the sample is not chosen randomly.
No, because not all people who enter the meat aisle use coupons.
Yes, because the manager asked everyone who entered the meat aisle.
No, because the sample is not chosen randomly. Sampling only those who enter the meat aisle may not represent the whole population of shoppers in the store, who may have different coupon usage habits. This method may introduce selection bias into the sample, which can affect the validity of the inference. Additionally, asking everyone who enters the meat aisle does not guarantee that the sample is representative of the entire population of meat aisle shoppers in the store. Therefore, the sampling method used by the store manager may not support a valid inference.
A quality control manager wants to determine the percentage of defective light bulbs in the production line. Which of the following sampling methods would most likely lead to a valid inference?@bot
testing the last 4,000 bulbs in the production line
retesting 100 light bulbs that have already been tested
testing the first 2,000 light bulbs in the production line
testing every fiftieth light bulb in the production line
testing the last 4,000 bulbs in the production line
retesting 100 light bulbs that have already been tested
testing the first 2,000 light bulbs in the production line
testing every fiftieth light bulb in the production line
Testing every fiftieth light bulb in the production line would most likely lead to a valid inference. This is because this method uses systematic random sampling, which selects every fiftieth light bulb from the production line, creating a representative sample that is spread out throughout the production process. This approach ensures that the sample contains light bulbs from different batches and production stages, that help to capture the variability in the production process. Therefore, by using this method, the quality control manager can obtain a more accurate estimate of the percentage of defective light bulbs in the production line.
Avery randomly selects 50 colored pencils from a basket and finds that 2 are not sharpened. If the basket contains 300 colored pencils, how many would you expect to be unsharpened?@bot
2
120
12
20
2
120
12
20
If Avery randomly selects 50 colored pencils from a basket and finds that 2 are not sharpened, we can use proportionality to estimate how many colored pencils in the entire basket are unsharpened.
The proportion of unsharpened colored pencils in Avery's sample is:
2/50 = 0.04
This indicates that 4% of the colored pencils in the basket are unsharpened.
To estimate the number of unsharpened pencils in the basket, we can multiply this proportion by the total number of colored pencils:
0.04 x 300 = 12
Therefore, we would expect 12 of the 300 colored pencils in the basket to be unsharpened. Hence, the answer is 12.
The proportion of unsharpened colored pencils in Avery's sample is:
2/50 = 0.04
This indicates that 4% of the colored pencils in the basket are unsharpened.
To estimate the number of unsharpened pencils in the basket, we can multiply this proportion by the total number of colored pencils:
0.04 x 300 = 12
Therefore, we would expect 12 of the 300 colored pencils in the basket to be unsharpened. Hence, the answer is 12.
There are 628 students in Tan’s high school. Tan surveys 120 randomly chosen students about their favorite movie genre. The results are as follows.
Movie genre Number of students/Frequency
Science Fiction 24
Horror 11
Comedy 27
Action 10
Animated 48
Based on Tan’s sample data, approximately how many students in the school prefer animated movies?
@bot
251
141
52
125
Movie genre Number of students/Frequency
Science Fiction 24
Horror 11
Comedy 27
Action 10
Animated 48
Based on Tan’s sample data, approximately how many students in the school prefer animated movies?
@bot
251
141
52
125
Based on Tan's sample data, approximately how many students in the school prefer animated movies?
Since 48 out of 120 students surveyed preferred animated movies:
48/120 = 0.4
This suggests that 40% of the student population in Tan's high school prefers animated movies.
To calculate how many students in the school prefer animated movies, we can multiply this percentage by the total number of students:
0.4 x 628 = 251
Therefore, approximately 251 students in Tan's high school prefer animated movies. Therefore, the answer is 251.
Since 48 out of 120 students surveyed preferred animated movies:
48/120 = 0.4
This suggests that 40% of the student population in Tan's high school prefers animated movies.
To calculate how many students in the school prefer animated movies, we can multiply this percentage by the total number of students:
0.4 x 628 = 251
Therefore, approximately 251 students in Tan's high school prefer animated movies. Therefore, the answer is 251.
There are 528 students in Pablo’s high school. Pablo surveys 130 randomly chosen students about their favorite ice cream flavor. The results are as follows.
Ice cream flavor Number of students/Frequency
Strawberry 29
Butter Pecan 31
Chocolate 43
Orange Sherbet 10
Vanilla 17
Based on Pablo’s sample data, approximately how many students in the school prefer orange sherbet?
@bot
110
41
195
45
Ice cream flavor Number of students/Frequency
Strawberry 29
Butter Pecan 31
Chocolate 43
Orange Sherbet 10
Vanilla 17
Based on Pablo’s sample data, approximately how many students in the school prefer orange sherbet?
@bot
110
41
195
45
Based on Pablo's sample data, approximately how many students in the school prefer orange sherbet?
Since 10 out of 130 students surveyed preferred orange sherbet:
10/130 = 0.077
This suggests that about 7.7% of the student population in Pablo's high school prefers orange sherbet.
To calculate how many students in the school prefer orange sherbet, we can multiply this percentage by the total number of students:
0.077 x 528 ≈ 40.7 ≈ 41
Therefore, approximately 41 students in Pablo's high school prefer orange sherbet. Therefore, the answer is 41.
Since 10 out of 130 students surveyed preferred orange sherbet:
10/130 = 0.077
This suggests that about 7.7% of the student population in Pablo's high school prefers orange sherbet.
To calculate how many students in the school prefer orange sherbet, we can multiply this percentage by the total number of students:
0.077 x 528 ≈ 40.7 ≈ 41
Therefore, approximately 41 students in Pablo's high school prefer orange sherbet. Therefore, the answer is 41.
The ages, in years, of randomly selected employees are 34, 41, 28, 35, 27, 44, 48, 29, 33, and 39. Determine the mean age.@bot
35.8
36.8
39.8
37.8
35.8
36.8
39.8
37.8
To determine the mean age of the randomly selected employees, we need to sum their ages and divide by the total number of employees.
The sum of the ages is:
34 + 41 + 28 + 35 + 27 + 44 + 48 + 29 + 33 + 39 = 358
To get the mean age, we divide the sum of the ages by the total number of employees:
358/10 ≈ 35.8
Therefore, the mean age of the randomly selected employees is approximately 35.8 years. Hence, the answer is 35.8.
The sum of the ages is:
34 + 41 + 28 + 35 + 27 + 44 + 48 + 29 + 33 + 39 = 358
To get the mean age, we divide the sum of the ages by the total number of employees:
358/10 ≈ 35.8
Therefore, the mean age of the randomly selected employees is approximately 35.8 years. Hence, the answer is 35.8.
@ bot what is the average of 8,6,4,2,1
To find the average of 8, 6, 4, 2, and 1, we add these numbers together and divide by the total number of values:
(8 + 6 + 4 + 2 + 1)/5 = 21/5 = 4.2
Therefore, the average of 8, 6, 4, 2, and 1 is approximately 4.2.
(8 + 6 + 4 + 2 + 1)/5 = 21/5 = 4.2
Therefore, the average of 8, 6, 4, 2, and 1 is approximately 4.2.
For 10 consecutive days, Anthony recorded the daily high temperatures in Dayton and Laredo. The table shows the data.
Daily High Temperatures (in °F)
Dayton 77 82 85 87 90 85 79 86 91 88
Laredo 81 79 80 86 88 92 82 88 84 87
Which city has a higher median daily high temperature? How much higher is this city’s median than the other city’s median daily high temperature?
@bot
Dayton has a higher median daily high temperature than Laredo by 0.3°F.
Laredo has a higher median daily high temperature than Dayton by 1°F.
Dayton has a higher median daily high temperature than Laredo by 0.5°F.
Laredo has a higher median daily high temperature than Dayton by 0.5°F.
Daily High Temperatures (in °F)
Dayton 77 82 85 87 90 85 79 86 91 88
Laredo 81 79 80 86 88 92 82 88 84 87
Which city has a higher median daily high temperature? How much higher is this city’s median than the other city’s median daily high temperature?
@bot
Dayton has a higher median daily high temperature than Laredo by 0.3°F.
Laredo has a higher median daily high temperature than Dayton by 1°F.
Dayton has a higher median daily high temperature than Laredo by 0.5°F.
Laredo has a higher median daily high temperature than Dayton by 0.5°F.
To determine which city has a higher median daily high temperature, we need to arrange the temperatures in order from lowest to highest and find the middle value.
For Dayton: 77 79 82 85 85 86 87 88 90 91
The two middle values are 86 and 87, so the median temperature for Dayton is (86 + 87)/2 = 86.5°F.
For Laredo: 79 80 81 82 84 86 87 88 88 92
The two middle values are 86 and 87, so the median temperature for Laredo is (86 + 87)/2 = 86.5°F.
Both cities have the same median daily high temperature of 86.5°F, so neither city has a higher median temperature. Therefore, none of the given answer choices are correct.
For Dayton: 77 79 82 85 85 86 87 88 90 91
The two middle values are 86 and 87, so the median temperature for Dayton is (86 + 87)/2 = 86.5°F.
For Laredo: 79 80 81 82 84 86 87 88 88 92
The two middle values are 86 and 87, so the median temperature for Laredo is (86 + 87)/2 = 86.5°F.
Both cities have the same median daily high temperature of 86.5°F, so neither city has a higher median temperature. Therefore, none of the given answer choices are correct.
The following data set represents the highway fuel efficiency in miles per gallon (mpg) of randomly selected cars from two car companies.
Car Company A: 35, 28, 35, 30, 31, 38, 35, 30
Car Company B: 29, 33, 36, 27, 34, 34, 34, 25
Which of the following statements is true?
@bot
The cars from Company A have higher median highway fuel efficiency than Company B.
The cars from both companies have the same mean, median, and modal highway fuel efficiency.
The cars from Company B have higher modal highway fuel efficiency than Company A.
The cars from Company A have a higher mean highway fuel efficiency that Company B.
Car Company A: 35, 28, 35, 30, 31, 38, 35, 30
Car Company B: 29, 33, 36, 27, 34, 34, 34, 25
Which of the following statements is true?
@bot
The cars from Company A have higher median highway fuel efficiency than Company B.
The cars from both companies have the same mean, median, and modal highway fuel efficiency.
The cars from Company B have higher modal highway fuel efficiency than Company A.
The cars from Company A have a higher mean highway fuel efficiency that Company B.
To determine which statement is true, we need to find the mean, median, and mode of the highway fuel efficiency for each car company:
For Company A:
Mean: (35 + 28 + 35 + 30 + 31 + 38 + 35 + 30) / 8 = 32.5
Median: (28, 30, 30, 31, 35, 35, 35, 38) → median = 33
Mode: 35
For Company B:
Mean: (29 + 33 + 36 + 27 + 34 + 34 + 34 + 25) / 8 = 31.25
Median: (25, 27, 29, 33, 34, 34, 34, 36) → median = 33.5
Mode: 34
Based on these calculations, we can see that the following statement is true:
- The cars from Company A have a higher mode highway fuel efficiency than Company B.
None of the other statements are true as:
- The median highway fuel efficiency is higher for cars from Company B.
- The mean highway fuel efficiency is higher for cars from Company A.
- The cars from both companies don't have the same mean, median, and mode highway fuel efficiency.
Therefore, the answer is "The cars from Company A have a higher mode highway fuel efficiency than Company B."
For Company A:
Mean: (35 + 28 + 35 + 30 + 31 + 38 + 35 + 30) / 8 = 32.5
Median: (28, 30, 30, 31, 35, 35, 35, 38) → median = 33
Mode: 35
For Company B:
Mean: (29 + 33 + 36 + 27 + 34 + 34 + 34 + 25) / 8 = 31.25
Median: (25, 27, 29, 33, 34, 34, 34, 36) → median = 33.5
Mode: 34
Based on these calculations, we can see that the following statement is true:
- The cars from Company A have a higher mode highway fuel efficiency than Company B.
None of the other statements are true as:
- The median highway fuel efficiency is higher for cars from Company B.
- The mean highway fuel efficiency is higher for cars from Company A.
- The cars from both companies don't have the same mean, median, and mode highway fuel efficiency.
Therefore, the answer is "The cars from Company A have a higher mode highway fuel efficiency than Company B."
The numbers of miles Ron biked are 31, 35, 49, 32, 45, 29, 33, 28, and 40.
Determine the range of this data set.@bot
35.8 miles
21 miles
9 miles
18 miles
Determine the range of this data set.@bot
35.8 miles
21 miles
9 miles
18 miles
To determine the range of this data set, we subtract the smallest value in the set from the largest value:
Range = Largest value - Smallest value
The smallest value in the set is 28, and the largest value is 49.
Range = 49 - 28 = 21
Therefore, the range of this data set is 21 miles. Hence, the answer is 21 miles.
Range = Largest value - Smallest value
The smallest value in the set is 28, and the largest value is 49.
Range = 49 - 28 = 21
Therefore, the range of this data set is 21 miles. Hence, the answer is 21 miles.
Which of the following data sets has the smallest range? @bot
{324, 318, 367, 312, 389, 337}
{148, 145, 117, 148, 199, 172}
{37, 19, 40, 54, 75, 68}
{50, 30, 10, 0, 80, 100}
{324, 318, 367, 312, 389, 337}
{148, 145, 117, 148, 199, 172}
{37, 19, 40, 54, 75, 68}
{50, 30, 10, 0, 80, 100}
@bot Which of the following data sets has the smallest range?
{324, 318, 367, 312, 389, 337}
{148, 145, 117, 148, 199, 172}
{37, 19, 40, 54, 75, 68}
{50, 30, 10, 0, 80, 100}
{324, 318, 367, 312, 389, 337}
{148, 145, 117, 148, 199, 172}
{37, 19, 40, 54, 75, 68}
{50, 30, 10, 0, 80, 100}
@bot can you answer what I just said?
7 answers