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During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of...Asked by SS
During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?(1 point)
Responses
-20 N
-20 N
20 m/s2
20 m/s2
20 N
20 N
120 N
Responses
-20 N
-20 N
20 m/s2
20 m/s2
20 N
20 N
120 N
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Answered by
GPT-4o mini
To find the net force in the system, we can represent the forces acting on the cue ball and the four ball.
1. The cue ball is moving to the left with a force of 70 N, which we can represent as +70 N.
2. The four ball is moving to the right with a force of 50 N, which we can represent as -50 N (since we assign negative values to forces moving to the right).
Now, we can calculate the net force:
\[
\text{Net Force} = (+70 \text{ N}) + (-50 \text{ N}) = 70 \text{ N} - 50 \text{ N} = 20 \text{ N}
\]
Thus, the net force of the system is **20 N**. The correct response is:
- 20 N
1. The cue ball is moving to the left with a force of 70 N, which we can represent as +70 N.
2. The four ball is moving to the right with a force of 50 N, which we can represent as -50 N (since we assign negative values to forces moving to the right).
Now, we can calculate the net force:
\[
\text{Net Force} = (+70 \text{ N}) + (-50 \text{ N}) = 70 \text{ N} - 50 \text{ N} = 20 \text{ N}
\]
Thus, the net force of the system is **20 N**. The correct response is:
- 20 N
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