During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?(1 point)

Question

Responses

-20 N
-20 N

120 N
120 N

20 N
20 N

20 m/s2

Answer 1

To determine the net force of the system, we need to account for the directions of the forces assigned positive and negative values.

• The cue ball is moving to the left with a force of 70 N (which we will consider as positive).
• The four ball is moving to the right with a force of 50 N (which we will consider as negative).

Now, we can calculate the net force:

\[ \text{Net Force} = \text{Force Left} + \text{Force Right} = 70 , N + (-50 , N) = 70 , N - 50 , N = 20 , N. \]

Since the leftward direction (for the cue ball) is taken as positive and the rightward direction (for the four ball) is taken as negative, the net force is:

\[ \text{Net Force} = 20 , N \text{ (to the left)}. \]

So, the correct response is:

20 N.