Total vector force = 50 i + 120 j
Total force magnitude = sqrt[(50)^2 + 120)^2] = 130 n
Total force direction = arctan(12/5) north of east. That would be 67.4 degrees in that direction
during a football game two players try to tackle another player.one player applies a force of 50.0 n to the east. a second player applies a force of 120.0 n to the north . what is the total applied force?and what is themagnitude and direction of the force
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1 answer