He is accelerated out of the cannon at a rate "a" given by
20 = (a/2) t^2 , where t = 0.91 s
Therefore
a = 48.3 m/s^2
Use F = m*a
for the average force F, in newtons.
F = 3719 N
During a circus performance, a 77-kg human cannonball is shot out of an 20-m-long cannon. If the human cannonball spends 0.91 s in the cannon, determine the average net force exerted on him in the barrel of the cannon.
1 answer
1 answer