Asked by Jade
During a Breathalyzer Test it was determined that 1.60mg of K2Cr2O7 was consumed by the above reaction. Calculate the number of milligrams of ethanol in the test sample.
Answers
Answered by
Jade
2K2Cr2O7 + 8H2SO4 + 3C2H5OH → 2Cr2(SO4)3 + 2K2SO4 + 3CH3COOH + 11H2O
Answered by
DrBob222
Convert 1.60 mg K2Cr2O7 to mg C2H5OH as follows:
mols K2Cr2O7 = 0.00160/molar mass K2Cr2O7.
Using the coefficients in the balanced equation, convert mols K2Cr2O7 to mols C2H5OH. That's mols K2Cr2O7 from above x (3 mols C2H5OH/2 mols K2Cr2O7) = mols K2Cr2O7 from above x (3/2) = ?
Then grams C2H5OH = mols C2H5OH x molar mass C2H5OH and convert g to mg.
mols K2Cr2O7 = 0.00160/molar mass K2Cr2O7.
Using the coefficients in the balanced equation, convert mols K2Cr2O7 to mols C2H5OH. That's mols K2Cr2O7 from above x (3 mols C2H5OH/2 mols K2Cr2O7) = mols K2Cr2O7 from above x (3/2) = ?
Then grams C2H5OH = mols C2H5OH x molar mass C2H5OH and convert g to mg.
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