To model the square mileage of developed land, \( y \), after \( x \) years with an initial amount of \( 8,500 \) square miles and an annual growth rate of \( 12% \), we use the formula for exponential growth:
\[ y = a(1 + r)^x \]
where:
- \( a \) is the initial amount (in this case, \( 8,500 \)),
- \( r \) is the growth rate (as a decimal; for \( 12% \), \( r = 0.12 \)),
- \( x \) is the number of years.
Thus, substituting in the values, we have:
\[ y = 8500(1 + 0.12)^x = 8500(1.12)^x \]
This matches option B:
B. \( y = 8,500(1.12)^x \)
So the correct answer is B.